Web16 de dez. de 2004 · The k-Local Hamiltonian problem is a natural complete problem for the complexity class QMA, the quantum analog of NP.It is similar in spirit to MAX-k-SAT, which is NP-complete for k ≥ 2.It was known that the problem is QMA-complete for any k ≥ 3. On the other hand 1-Local Hamiltonian is in P, and hence not believed to be QMA-complete. WebWe study the time complexity of (d,k)-CSP, the problem of deciding satisfiability of a constraint system with n variables, domain size d, and at most k variables per constraint.We are interested in the question how the domain size d influences the complexity of deciding satisfiability. We show, assuming the Exponential Time Hypothesis, that two special …
On the parameterized complexity of (k,s)-SAT - ScienceDirect
Web1 de fev. de 2024 · The complexity of weighted team definability for logics with team semantics is studied in terms of satisfaction of first-order formulas with free relation variables and several results are shown on the complexity of this problem for dependence, independence, and inclusion logic formulas. In this article, we study the complexity of … Web13 de abr. de 2014 · Complexity theoretic limitations on learning DNF's. Amit Daniely, Shai Shalev-Shwatz. Using the recently developed framework of [Daniely et al, 2014], we show that under a natural assumption on the complexity of refuting random K-SAT formulas, learning DNF formulas is hard. Furthermore, the same assumption implies the hardness … t shirt wholesaler uk
The Complexity of k-SAT Proceedings of the Fourteenth Annual …
WebSat and Max Sat are among the most prominent problems for which local search algorithms have been successfully applied. A fundamental task for such an algorithm is to increase the number of clauses satisfied by a given truth assignment by flipping the truth values of at most k variables (k-flip local search).For a total number of n variables the size of the … Webcomplexity of k-SAT increases with increasing k.Define s k (for 3) to be the infimum of f : there exists an O (2 n) algorithm for solving k-SAT g. Define ETH (Exponential-Time Hypothesis) for k-SAT as follows: for k 3, s k > 0. In other words, for , k-SAT does not have a subexponential-time algorithm. In this paper, we show that s k is an ... Web30 de abr. de 2024 · If the strong exponential time hypothesis (SETH) holds, then this is not much harder than SAT itself, so under SETH the complexity of SAT, ALL-SAT, #SAT is the same (up to polynomial factors). Moreover, without SETH you can claim that given access to a # S A T oracle, you can output all satisfying assignments in time k ( φ) p o l y ( n, m ... phil sturholm